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  • January 19, 2025
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Last week Heron’s formula came up in the post An Unexpected Triangle. Given the lengths of the sides of a triangle, there is a simple expression for the area of the triangle.

A = sqrt{s(s-a)(s-b)(s-c)}

where the sides are a, b, and c and s is the semiperimeter, half the perimeter.

Is there an analogous formula for the area of a quadrilateral? Yes and no. If the quadrilateral is cyclic, meaning there exists a circle going through all four of its vertices, then Brahmagupta’s formula for the area of a quadrilateral is a direct generalization of Heron’s formula for the area of a triangle. If the sides of the cyclic quadrilateral are a, b, c, and d, then the area of the quadrilateral is

A = sqrt{s(s-a)(s-b)(s-c)(s-d)}

where again s is the semiperimeter.

But in general, the area of a quadrilateral is not determined by the length of its sides alone. There is a more general expression, Bretschneider’s formula, that expresses the area of a general quadrilateral in terms of the lengths of its sides and the sum of two opposite angles. (Either pair of opposite angles add to the same value.)

A = sqrt {(s-a)(s-b)(s-c)(s-d) - abcd , cos^2 left(frac{alpha + gamma}{2}right)}

In a cyclic quadrilateral, the opposite angles α and γ add up to π, and so the cosine term drops out.

Related posts

  • Shoelace formula for polygon area
  • Area of a triangle in the complex plane
  • Area of a quadrilateral as a determinant

The post Area of a quadrilateral from the lengths of its sides first appeared on John D. Cook.

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